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If (ax^2 + Bx + C) Equals Zero, Who Cares About X?
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if (ax^2 + bx + c) equals zero, who cares about x?
Related:
define BITCOUNT(x) (((BX_(x)+(BX_(x)>>4)) & 0x0F0F0F0F) % 255) #define BX_(x) ((x) - (((x)>>1)&0x77777777) \ - (((x)>>2)&0x33333333) \ - (((x)>>3)&0x11111111)) -- Count the number of bits in a word.
Who says '1+1' REALLY equals '2'?
If you get to the end, who cares about the means?
Reading, writing. Who cares about arithmetic?
1) X=Y ; Given 2) X^2=XY ; Multiply both sides by X 3) X^2-Y^2=XY-Y^2
Subtract Y^2 from both sides 4) (X+Y)(X-Y)=Y(X-Y) ...
The man who comes with a tale about others has himself an ax to grind. -- Chinese proverb
Coddle criminals, who cares about the victims! -- Liberal Rule #16